How do you write the linear equation #-12x+8y=-32# in slope-intercept form?

1 Answer
Pitufox27
Dec 25, 2016

The equation of the line #-12 x + 8 y = - 32# is expressed as #y = 3/2 x - 4# in slope-intercept form.

Explanation:

Just clear the #"y"#:

#- 12 x + 8 y = - 32 rArr 8 y = 12 x - 32 rArr#

#rArr y = {12 x - 32}/8 rArr y = 12/8 x - 32/8 rArr#

#rArr y = 3/2 x - 4#.

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