How do you solve 2x2+11x6=0 using the quadratic formula?

1 Answer
Dec 26, 2016

The two solutions are x=0.50 and x=6

Explanation:

Since this question is given in standard form, meaning that it follows the form: ax2+bx+c=0, we can use the quadratic formula to solve for x:
https://mathbitsnotebook.com/Algebra1/Quadratics/QDquadform.htmlhttps://mathbitsnotebook.com/Algebra1/Quadratics/QDquadform.html

I think it's worthwhile to mention that a is the number that has the x2 term associated with it. Thus, it would be 2x2 for this question.b is the number that has the x variable associated with it and it would be 11x, and c is a number by itself and in this case it is -6.

Now, we just plug our values into the equation like this:

x=(11)±(11)24(2)(6)2(2)

x=11±121+484

x=11±1694

For these type of problems, you will obtain two solutions because of the ± part. So what you want to do is add -11 to 169 together and divide that by 4:

x=11+1694
x=24=0.50

Now, we subtract 169 from -11 and divide by 4:

x=111694
x=244=6

Therefore, the two possible solutions are:
x=0.5 and x=6