How do you find the values of the six trigonometric functions given #sintheta=0# and #sectheta=-1#?

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Answer 1 · 2016-12-26T08:08:07

#sintheta=0; costheta=-1; tan theta=0; cottheta=oo; sectheta=-1;csctheta=oo#

Since

#cos theta=1/sectheta=1/-1=-1#,

and

#sintheta=0#,

then

#tan theta=sintheta/costheta=0/-1=0#

#cot theta=1/tantheta=oo#

#csctheta=1/sintheta=oo#