How do you solve the system #3x+2y=2, -2x+y=8#?

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Answer 1 · 2016-12-26T09:03:12

#x=-2#
#y=4#

Since, by the second equation, it is

#y=8+2x# #color(red)((1))#

you can put it in the first equation and get:

#3x+2(8+2x)=2#

Then you multiply and get:

#3x+16+4x=2#

that's

#7x=2-16#

#7x=-14#

#x=-2#

Then you put it in #color(red)((1))# and get:

#y=8+2(-2)=8-4=4#