A triangle has sides A, B, and C. If the angle between sides A and B is #(pi)/4#, the angle between sides B and C is #(2pi)/3#, and the length of side B is 5, what is the area of the triangle?

1 Answer
Dec 26, 2016

Let

1.the angle between sides A and B opposite to side C is #gamma=pi/4#

2.the angle between sides B and C opposite to side A is #alpha=(2pi)/3#

3.the angle between sides C and A opposite to side B is #beta=pi-(2pi)/3-pi/4=pi/12#

By sine law of triangle

#C/singamma=B/sinbeta#

#=>C=(Bsingamma)/sinbeta#

Area if the triangle

#Delta=1/2BxxCsinalpha#

#=1/2B^2(sinalphaxxsingamma)/sinbeta#

#=1/2xx5^2(sin((2pi)/3)sin(pi/4))/sin(pi/12)#

#~~29.57squnit#