How do you differentiate #y=sin(e^x)#?
1 Answer
Dec 27, 2016
Explanation:
Using the chain rule, along with the known derivatives
#d/dxsin(x) = cos(x)# #d/dxe^x = e^x#
we have
#=cos(e^x)[d/dxe^x]#
#=cos(e^x)[e^x]#
#=e^xcos(e^x)#
