How do you convert #y= -x^2+3xy-4 # into a polar equation? Trigonometry The Polar System Converting Between Systems 1 Answer Andrea S. Dec 29, 2016 #r^2costheta(3sintheta-1) +rsintheta+4=0# Explanation: Substitute: #x=rcostheta# #y=rsintheta# #rsintheta = -r^2costheta +3r^2sinthetacostheta-4# or: #r^2costheta(3sintheta-1) +rsintheta+4=0# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1231 views around the world You can reuse this answer Creative Commons License