How do you find the quotient #-1/3div (-1 1/5)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Alan P. Dec 31, 2016 #-1/3div(-1 1/5) =5/18# Explanation: #(-1/3)div(-1 1/5)# #color(white)("XXX")=(-1/3)div(-6/5)# #color(white)("XXX")=(-1/3)xx(-5/6)# #color(white)("XXX")=cancel(""(-1))xx1/3xxcancel(""(-1))xx5/6# #color(white)("XXX")=(1xx5)/(3xx6)# #color(white)("XXX")=5/18# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 2192 views around the world You can reuse this answer Creative Commons License