I have 6 faces, 8 vertices, and 12 edges. Which figure am l?

1 Answer
Jan 1, 2017

It is a cuboid or quadrilaterally-faced hexahedron.

Explanation:

There is no unique formula for getting the figure. However, according to Euler's Polyhedral Formula, in a convex polyhedra, if V is the number of vertices, F is number of faces and E is number of edges than V-E+F=2.

It is apparent that with 6 faces, 8 vertices, and 12 edges, then 8-12+6=2, hence it is a valid polyhedra.

However, it is evident that the figure is a cuboid or quadrilaterally-faced hexahedron, as it too has 6 faces, 8 vertices, and 12 edges.
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