How do you solve #(x-2)/3+1/6=5/6#?

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Answer 1 · 2017-01-01T10:09:34

#x=4#

#(x-2)/3+1/6=5/6#

#(x-2)/3+1/6-5/6=0#

#(x-2)/3-4/6=0#

#(x-2)/3-2/3=0#

#((x-2)-2)/3=0#

multiply both sides by 3

#x-4=0#

#x=4#

substitute x= 4

#((4)-2)/3+1/6=5/6#

#2/3+1/6=5/6#

#(4+1)/6=5/6#

#5/6=5/6#