A line passes through #(2 ,9 )# and #(5 ,2 )#. A second line passes through #(3 ,8 )#. What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer

Answer: #(0, 15)#

Explanation:

First, find the slope of the first line by using

#"slope" = m = (y_2 - y_1) / (x_2 - x_1)#

In this case, you have

#m = (2 - 9)/(5 -2)= -7/3#

Now with the slope of #-7/3#, we have to find two coordinates with the exact same slope. So we put it in the slope formula

#(8- ?)/(3 - ?) = -7/3#

which is the slope we have to find. We could use #15# and #0#, and when we input them back into the equation the slope equals #-7/3#.

But since the slope formula is #m = (y_2 - y_1) / (x_2 - x_1)#, we often get confused and say #(15,0)# and forget it's #y# over #x#. So remember to switch them so #x=0# and #y=15#.

To continue, if something is parallel to another line they have the same slope.

If something is perpendicular it has the opposite reciprocal slope.