Question

Question #2c645

Answer 1

`n=637`

Explanation:

We know that `5^5=3125 > 2557` so the number of trailing zeroes is given by

`n=sum_(k=1)^4 floor(2557/5^k) = 511+102+20+4=637`

which is the number of `5` factors appearing in `2557` Those `5` multiplied by the `2` factors are responsible by the trailing zeroes.