Question

How do you write an equation for a line passing through the points (5,-1) and (-3,-2)?

Answer 1

The equation of the line in standard form is `x -8y = 13`

Explanation:

The slope of the line passing through `(5,-1) and (-3,-2)` is `m= (y_2-y_1)/(x_2-x_1)= (-2+1)/(-3-5)=(-1)/(-8)=1/8`

Let the equation of the line in slope-intercept form be `y=mx+c or y=1/8x+c` The point (5,-1) will satisfy the equation . So, `-1= 1/8*5+c or c= -1-5/8= -13/8`

Hence the equation of the line in slope-intercept form is `y= 1/8x-13/8`

The equation of the line in standard form is `y= 1/8x-13/8. or 8y =x-13 or x -8y = 13` {Ans]