If a projectile is shot at an angle of pi/2 and at a velocity of 37 m/s, when will it reach its maximum height??

1 Answer
Jan 5, 2017

We need to find the instant at which the projectile's vertical component of velocity is zero.

Explanation:

The vertical component of the velocity at time t is given by v(t)=u-g t, where u is the projectile's initial vertical component of velocity and g is the gravitational acceleration constant.

So we are required to solve 0=u-g t, which gives t=u/g

Now, u=37 sin (pi/2)m/s and we take g=10mbox{}m/s\mbox{}^2. So the final answer is t=37/10=3.7s.