How do you solve #12-12n=48#?

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Answer 1 · 2017-01-06T02:54:15

#color(purple)"n = - 3"#

#color(magenta)("Subtract 12 on both sides:")#

#cancel12-12n= 48#
#cancel-12# #color(white)(aaaa) -12#

12 cancels out on the left side, and when you subtract 12 from 48 on the right you get 36:

#-12n = 36#

#color(greeb)("Divide both sides by -12 to get n by itself.")#

#(cancel"-12"n)/cancel"-12"=(36)/-12#

Now you are just left with #n# on the left side and -3 on the right side.

Therefore,
#color(purple)"n = -3"#