Question

How do you simplify `sqrt(16r^6)`?

Answer 1

`4r^3`

Explanation:

The trick is to look for squared value and then to take them outside the square root but not in squared form.

Note that `16 = 4^2" and "r^6 = r^(3xx2)= (r^3)^2`

`sqrt(16r^6)" "->" "sqrt(4^2(r^3)^2)" "=" "4r^3`

If you wished to be really fussy consider this example:
`(-2)xx(-2)" " =" " +4" " =" "(+2)xx(+2)`

So we have: `sqrt(16r^6)" "->" "sqrt(4^2(r^3)^2)" "=" "+-4r^3`

I suspect they are just looking for `+4r^3` as the answer