Question

Question #0ed52

Answer 1

The answer assumes that
for part (a) charge `q` on the capacitor is already maximum charge it can hold.
For part (b) potential difference `V` across its plates is already at its maximum rated voltage.

We know that Capacitance `C` is defined in terms of stored charge in a capacitor as

`C-=Q/V`
where `Q =` magnitude of charge stored on each plate of the capacitor, and `V =` voltage applied to the plates. Its SI units are Farad `F`

(a) When charge is doubled. Assuming that there is no change in the applied voltage, as shown from the equation above, capacitance is doubled; `xx2`.

(b) When the potential difference `V` across plates it is tripled. Assuming that there is no change in the stored charge, from the equation above, capacitance becomes one third; `xx1/3`.