What is the formula weight of #Mg(BrO_4)_2#?
Current Version
Answer:
Explanation:
The formula weight of magnesium perbromate can be obtained by using the following equation:
atomic weight of element
First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:
 Mg has a molar mass of 24.31 g/mol
 Br has an atomic weight of 79.90 g/mol
 O has an atomic weight of 16.00 g/mol
There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol
From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.
There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol
Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:
Edit History

Changes  Side by side#312.11 "g/mol")# The formula weight of magnesium perbromate can be obtained by using the following equation: **atomic weight of element #xx#number of atoms given by subscript #=# formula mass** First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:  Mg has a molar mass of 24.31 g/mol  Br has an atomic weight of 79.90 g/mol  O has an atomic weight of 16.00 g/mol There is one magnesium atom, so the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) of Mg is just 24.31 g/mol From the chemical formula, we have 2 bromine atoms. Therefore, the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol. There are 8 oxygen atoms, so the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) has to be multiplied by 8, which gives you a value of 128.00 g/mol Now you want to add the mass of each atom together to obtain the formula mass of the entire compound: #color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")##312.11 g/"mol"# The formula weight of magnesium perbromate can be obtained by using the following equation: **atomic weight of element #xx#number of atoms given by subscript #=# formula mass** First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:  Mg has a molar mass of 24.31 g/mol  Br has an atomic weight of 79.90 g/mol  O has an atomic weight of 16.00 g/mol There is one magnesium atom, so the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) of Mg is just 24.31 g/mol From the chemical formula, we have 2 bromine atoms. Therefore, the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol. There are 8 oxygen atoms, so the [atomic mass](https://socratic.org/chemistry/afirstintroductiontomatter/atomicmassandisotopeabundance) has to be multiplied by 8, which gives you a value of 128.00 g/mol Now you want to add the mass of each atom together to obtain the formula mass of the entire compound: #color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")#
From
Answer:
#312.11 "g/mol")# Explanation:
The formula weight of magnesium perbromate can be obtained by using the following equation:
atomic weight of element
#xx# number of atoms given by subscript#=# formula massFirst, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:
 Mg has a molar mass of 24.31 g/mol
 Br has an atomic weight of 79.90 g/mol
 O has an atomic weight of 16.00 g/mol
There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol
From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.
There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol
Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:
#color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")# To
Answer:
#312.11 g/"mol"# Explanation:
The formula weight of magnesium perbromate can be obtained by using the following equation:
atomic weight of element
#xx# number of atoms given by subscript#=# formula massFirst, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:
 Mg has a molar mass of 24.31 g/mol
 Br has an atomic weight of 79.90 g/mol
 O has an atomic weight of 16.00 g/mol
There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol
From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.
There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol
Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:
#color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")# 
@kayla14 Kayla wrote an answer.
Answer:
#312.11 "g/mol")# Explanation:
The formula weight of magnesium perbromate can be obtained by using the following equation:
atomic weight of element
#xx# number of atoms given by subscript#=# formula massFirst, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:
 Mg has a molar mass of 24.31 g/mol
 Br has an atomic weight of 79.90 g/mol
 O has an atomic weight of 16.00 g/mol
There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol
From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.
There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol
Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:
#color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")#