# What is the formula weight of Mg(BrO_4)_2?

##### Current Version

$312.11 \frac{g}{\text{mol}}$

#### Explanation:

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

• Mg has a molar mass of 24.31 g/mol
• Br has an atomic weight of 79.90 g/mol
• O has an atomic weight of 16.00 g/mol

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{m a \ge n t a}{\text{24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol}}$

##### Edit History
• @kayla-14 Kayla updated the answer.
1 year ago
Changes | Side by side
312.11 "g/mol") The formula weight of magnesium perbromate can be obtained by using the following equation: **atomic weight of element xxnumber of atoms given by subscript = formula mass** First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O: - Mg has a molar mass of 24.31 g/mol - Br has an atomic weight of 79.90 g/mol - O has an atomic weight of 16.00 g/mol There is one magnesium atom, so the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) of Mg is just 24.31 g/mol From the chemical formula, we have 2 bromine atoms. Therefore, the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol. There are 8 oxygen atoms, so the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) has to be multiplied by 8, which gives you a value of 128.00 g/mol Now you want to add the mass of each atom together to obtain the formula mass of the entire compound: color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")
312.11 g/"mol" The formula weight of magnesium perbromate can be obtained by using the following equation: **atomic weight of element xxnumber of atoms given by subscript = formula mass** First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O: - Mg has a molar mass of 24.31 g/mol - Br has an atomic weight of 79.90 g/mol - O has an atomic weight of 16.00 g/mol There is one magnesium atom, so the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) of Mg is just 24.31 g/mol From the chemical formula, we have 2 bromine atoms. Therefore, the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol. There are 8 oxygen atoms, so the [atomic mass](https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance) has to be multiplied by 8, which gives you a value of 128.00 g/mol Now you want to add the mass of each atom together to obtain the formula mass of the entire compound: color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")
##### From

312.11 "g/mol")

#### Explanation:

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

• Mg has a molar mass of 24.31 g/mol
• Br has an atomic weight of 79.90 g/mol
• O has an atomic weight of 16.00 g/mol

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{m a \ge n t a}{\text{24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol}}$

##### To

$312.11 \frac{g}{\text{mol}}$

#### Explanation:

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

• Mg has a molar mass of 24.31 g/mol
• Br has an atomic weight of 79.90 g/mol
• O has an atomic weight of 16.00 g/mol

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{m a \ge n t a}{\text{24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol}}$

• @kayla-14 Kayla wrote an answer.
1 year ago

312.11 "g/mol")

#### Explanation:

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

• Mg has a molar mass of 24.31 g/mol
• Br has an atomic weight of 79.90 g/mol
• O has an atomic weight of 16.00 g/mol

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{m a \ge n t a}{\text{24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol}}$