Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 1.2?

1 Answer
Jan 8, 2017

log1.2=0.0792

Explanation:

As log9=0.9542. we have

log9=log3^2=2log3=0.9542 i.e. log3=0.9542/2=0.4771

Hence log1.2=log((4xx3)/10)=log4+log3-log10

= 0.6021+0.4771-1

= 1.0792-1

= 0.0792

We could have also done

log1.2=log(12/10)=log12-log10

= 1.0792-1=0.0792