A ball with a mass of 80 g80g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 16 (kg)/s^216kgs2 and was compressed by 1/5 m15m when the ball was released. How high will the ball go?

1 Answer
Jan 8, 2017

I tried this but check my maths.

Explanation:

We can consider:
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So basically we can write:
1/2kx^2=1/2mv^212kx2=12mv2
v=sqrt((kx^2)/m)=sqrt(8)=2.8m/sv=kx2m=8=2.8ms

We now use the kinematic relationship:
v_f^2=v_i^2+2ahv2f=v2i+2ah
With a=a= acceleration of gravity downwards and v_f=0vf=0 for the final velocity;
0=8-(2*9.8*h)0=8(29.8h)
h=8/(2*9.8)=0.4mh=829.8=0.4m
If we consider also the initial compression, the total vertical distance should be:
h+h_1=0.4+0.2=0.6mh+h1=0.4+0.2=0.6m