How do you find the derivative of #f(x) = sin x + 1/2 cot x#?

1 Answer
Jim G.
Jan 8, 2017

#f'(x)=cosx-1/2csc^2x#

Explanation:

The terms in f(x) have #color(blue)"standard derivatives"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(sinx)=cosx)color(white)(2/2)|)))#

#"and " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(cotx)=-csc^2x)color(white)(2/2)|)))#

#rArrf'(x)=cosx-1/2csc^2x#

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