Question

Is `f(x)=-2x^5-2x^3-12x^2-6x+1` concave or convex at `x=-1`?

Answer 1

f(x) is concave at x=1

Explanation:

You would get the first and the second derivative; then:

`f'(x)=-10x^4-6x^2-24x-6`

`f''(x)=-40x^3-12x-24`

`f''(1)=-40-12-24<0`

Since `f''(1)<0`, f(x) is concave at x=1