What is the vertex form of # y= (2x-3)(7x-12)+17x^2-13x#?

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Answer 1 · 2017-01-09T17:21:31

Vertex form of equation is #y=31(x-29/31)^2+275/31#

Vertex form of equation is #y=a(x-h)^2+k#

As we have #y=(2x-3)(7x-12)+17x^2-13x#

#=2x xx 7x-2x xx12-3xx7x-3xx(-12)+17x^2-13x#

#=14x^2-24x-21x+36+17x^2-13x#

#=31x^2-58x+36#

#=31(x^2-58/31x)+36#

#=31(x^2-2xx29/31x+(29/31)^2)+36-31xx(29/31)^2#

#=31(x-29/31)^2+36-841/31#

#=31(x-29/31)^2+275/31#
graph{(2x-3)(7x-12)+17x^2-13x [-5, 5, -2.88, 37.12]}