How do you rewrite the expression #(6x+15)div3# in standard form using the distributive property?
1 Answer
Jan 10, 2017
Explanation:
#(6x+15)÷3=1/3(6x+15)#
#"division by 3 is equivalent to multiplication by " 1/3#
#rArr(6x+15)/3=(6x)/3+15/3=2x+5#
#"and " color(red)(1/3)(6x+15)#
#=(color(red)(1/3)xx6x)+(color(red)(1/3)xx15)=2x+5#
