How do you evaluate ${log}_{7} 1$ $log_7 1$ ?

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Answer 1 · 2017-01-10T21:42:14

${log}_{7} (1) = 0$ $log_7(1)=0$

${log}_{b} (1) = 0$ $log_b(1)=0$ where $b$ $b$ is any real number.
$b^{0} = 1$ $b^0=1$

${log}_{7} (1) = 0$ $log_7(1)=0$

How do you evaluate log71log_7 1?