How do you simplify $(3 + 2 i) + (- 4 + 6 i)$ $(3+2i)+(-4+6i)$ ?

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Answer 1 · 2017-01-11T02:02:04

$- 1 + 8 i$ $-1+8i$

We add complex numbers by collecting real and imaginary terms separately:

$(3 + 2 i) + (- 4 + 6 i)$ $(3+2i)+(-4+6i)$
$\ \ \ \ \ \ \ = 3+2i-4+6i$
$\ \ \ \ \ \ \ = 3-4+2i+6i$
$\ \ \ \ \ \ \ = -1+8i$

How do you simplify (3+2i)+(-4+6i)(3+2i)+(−4+6i)(3+2i)+(-4+6i)?