Question

How do you find the exact value of `ln e^2+lne^5`?

Answer 1

`lne^2+lne^5 = 7`

Explanation:

Remember: `lne^a = a`

`:. lne^2+lne^5 = 2+5 =7`

Alternatively you could approach this problem as follows:

`lne^2+lne^5 = ln (e^2 xx e^5)`

`=lne^7 = 7`