How do you solve #y=4x-3, 2y-3x=4#?
1 Answer
Jan 11, 2017
Explanation:
Since we are given
#y=4x-3# we can substitute this into the other equation and solve for x.
#rArr2(color(red)(4x-3))-3x=4# distributing.
#8x-6-3x=4# add 6 to both sides and simplify.
#5xcancel(-6)cancel(+6)=4+6#
#rArr5x=10# To solve for x, divide both sides by 5
#(cancel(5) x)/cancel(5)=10/5rArrx=2# We can now substitute x = 2 into y = 4x - 3 to find y.
#x=2toy=(4xx2)-3=8-3=5#
