Question

How do you graph `y=log_(1/2)x`?

Answer 1

The standard graph of `lnx` scaled by: `-1/ln2`

Explanation:

Remember: `log_b a = lna/lnb`

In our example: `y= log_(1/2) x`

Hence: `y = lnx/ln(1/2) = lnx * -1/ln2`

Thus:
The graph of `y` is the standard graph of `lnx` scaled by: `-1/ln2`

The graph of `y` is shown below:

graph{ lnx * -1/ln2 [-2.114, 15.666, -4.47, 4.42]}