Question

How do you write the prime factorization of `28x^2y`?

Answer 1

`2xx2xx7xx x xx x xx y`
[With the assumption that `x` and `y` are prime.]

Explanation:

The prime factors of 28 are: `2xx2xx7`

Since `x` are `y` are unknowns, I will express the factors of `x^2y` as: `x xx x xx y` [With the assumption that `x` and `y` are prime.]

Hence the prime factorisation of `28x^2y` is: `2xx2xx7xx x xx x xx y`