A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $15$ and the height of the cylinder is $4$ . If the volume of the solid is $18 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2017-01-14T13:49:48

The area is $=2pi$

Volume of the cone $=V_(co)=1/3*a*h_(co)$

Volume of the cylinder $=V_(cy)=a*h(cy)$

Volume of solid $V=V_(co)+V_(cy)$

$V=1/3*a*h_(co)+a*h(cy)=18pi$

So,

$1/3*a*15+a*4=18pi$

$9a=18pi$

$a=2pi$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 15 15 and the height of the cylinder is 4 4 . If the volume of the solid is 18 pi18 pi, what is the area of the base of the cylinder?