Question

A tire has a pressure of 780 mmHg at 27 deg C. If the tire is heated to 47 deg C on hot pavement, what will the new pressure be?

Answer 1

We use `(p_1)/T_1=(p_2)/T_2`, with `T` in `K`

Explanation:

`27^oC=27+273K=300K`
`47^oC=47+273K=320K`

The equation above can be re-written to:
`p_2=T_2/T_1xxp_1=320/300xx780=832mmHg`