How do you find the slant asymptote of #f(x) =( x^2 + 3x - 3) / (x+4)#?
2 Answers
The slant asymptote is
Explanation:
Let's do the long division
Therefore,
Let
So,
The slant asymptote is
graph{(y-(x^2+3x-3)/(x+4))(y-x+1)=0 [-10, 10, -5, 5]}
Slant asymptote:
Explanation:
By division,
Rearranged,
asymptotes
Separately,
y-x+1=0 gives a slant asymptote and
x+4=0 gives a vertical asymptote.
graph{((y-x+1)(x+4)-1)(y-x+1)(x+0.000001y+4)=0 [-23, 23.02, -12.7, 12.6]}