How do you graph #f(x) = x^5-6x^4+9x^3#?

1 Answer
Jan 15, 2017

Graph is inserted.

Explanation:

#f=x^3(x-3)^2# = 0, at x = 0, 0, 0, 3 and 3.#

#f'=x^2(x-3)(5x-9)=0, at x = 0, 0, 9/5 and 3.#

#f'=2x(10x^2-36x+27)=0, at x = 0 and 1.8+-sqrt0.52#

Look for all these aspects depicted, in the inserted graph.

As #x to +- oo, f to +-oo#, on the right and left, respectively,

graph{x^3(x-3)^2x^2 [-10, 10, -50, 50]}