Question

How do you simplify `sqrt108/sqrt3`?

Answer 1

`sqrt(108)/sqrt(3) = 6`

Explanation:

Use the identity:

`sqrt(a/b) = sqrt(a)/sqrt(b)`

(which holds for any `a, b > 0`)

So:

`sqrt(108)/sqrt(3) = sqrt(108/3) = sqrt(36) = sqrt(6^2) = 6`