Question

How do you solve the inequality `4x^2+20x+25>=0`?

Answer 1

The inequality is true for all values of `x`

Explanation:

`4x^2+x+25>=0`
Factorise
`(2x+5)(2x+5)>=0`
`(2x+5)^2>=0`
Every square is greater than or equal to 0