Question

How do you solve the quadratic using the quadratic formula given `3a^2=6a-3`?

Answer 1

`a=1`

Explanation:

Rearrange:
`3a^2-6a+3=0`

Use the formula `a=(-b+-sqrt(b^2-4ac))/(2a)` taking care not to get the `a`'s muddled

Formula Problem
a 3
b -6
c 3
x a

`a=(-(-6)+-sqrt((-6)^2-4 xx 3 xx 3))/(2 xx 3)`
`a=(6+-0)/(2 xx 3)`
`a=1` (repeated root).

Check: `3xx(1)^2=3` and `6xx(1)-3=3`

If you get muddled over the `a`'s just replace all the `a`'s with `x`'s, apply the formula, then at the step replace the `x` with `a`.