Question

How do you find the exact value of `log_4 16^1.2`?

Answer 1

I got `2.4`

Explanation:

I would first use a property of logs to deal with the exponent of the argument and write:
`1.2log_4(16)=`

Then I would use the definition to solve the log as:
`log_4(16)=2`
[Because `4^2=16`]

So I have:
`1.2*2=2.4`