How do you factor #12x²-3x#?
1 Answer
Jan 19, 2017
Explanation:
We have to find the combined
#color(blue)"common factor"# of the 2 terms.The factors of 12 are
#1,2,color(red)(3),4,6,12# The factors of 3 are
#1,color(red)(3)# Hence the common factor of 12 and 3 is
#color(red)(3)#
#x^2=x xx color(magenta)(x)" and " x=1xxcolor(magenta)(x)# Hence the common factor of
#x^2" and " x" is " color(magenta)(x)# The combined common factor of the 2 terms is 3x
#rArr12x^2-3x=3x(4x-1)#