Question

A spring with a constant of `7 (kg)/(s^2)` is lying on the ground with one end attached to a wall. An object with a mass of `4 kg` and speed of `9 m/s` collides with and compresses the spring until it stops moving. How much will the spring compress?

Answer 1

6,8 m

Explanation:

The Kinetic energy of the object `Ek = 1/2 mV^2`becomes the elastic energy of the spring `Es= 1/2 mX^2` so
`mV^2 = K X^2`
`X= sqrt (m/k) V`
`X= sqrt ((4kg)/(7kg/s^2)) 9 m/s` = 6,8 m