Question

Question #89bdd

Answer 1

Here it is given that the space station is spinning with an angular speed (`omega`) of 2 rpm

So `omega=2rp m=(2xx2pi)/60"radian/s"=pi/15"rad/s"`

So centripetal acceleration produced `a=omega^2R`, where R is the the radius of the space station. As per given condition this acceleration `a` will be equal to the artificial acceleration due to gravity `g =10"m/"s^2` experienced by an astronaut.

So `g=omega^2R`

`R=g/omega^2=10/(pi/15)^2m=2250/pi^2m~~228m`