Question

Question #fca8b

Answer 1

The displacement (`x`) of the particle with time (`t`) along x-axis is given here by the following relation

`x=2-5t+6t^2`

Differntiating the relation w.r to we get the velocity of the particle at tth instant. So

`v(t)=(dx)/(dt)=0-5+12t`

Hence initially when `t=0` we have velocity
`v(0)=-5+12xx0=-5unit`