For what values of #m# is #F(x) = (m^2+m+1)x# increasing or decreasing?
1 Answer
Jan 22, 2017
Explanation:
Note that:
#m^2+m+1 = m^2+2(1/2)m+1/4+3/4#
#color(white)(m^2+m+1) = (m+1/2)^2+3/4 >= 3/4# for any#m in RR#
Hence