How do you find the vertical, horizontal or slant asymptotes for (e^x)/(1+e^x)?

1 Answer
Jan 22, 2017

Horizontal asymptotes : y = 1 rarr and y = 0 larr. See the asymptotes-inclusive Socratic graph.

Explanation:

As x to oo, e^x/(1+e^x)=1/(1+e^(-x)) to 1 and

as x to -oo, it to0.

y-intercept ( x = 0 ) : 1/2

graph{(e^x/(1+e^x)-y)(y-1.1)(y+.01)=0 [-10, 10, -5, 5]}