How do you graph #2x-1=y#?

1 Answer

See below

Explanation:

This equation is in slope-intercept form so the values for graphing are provided.

The general form is

#color(pink)(| bar(ul(color(black)(y=color(red)mcolor(black)x+color(green)b)) |)#

with #color(red)m# being the slope and #color(green)b# being the y-intercept.

We have:

#y=color(red)2xcolor(green)(-1)#

The y-intercept is at #(0,-1)#

We can then apply the slope. #color(red)m="rise"/"run"=2#, which means we can move two units up for every one unit to the right. Starting from #(0,-1)#, we can move two units up and one unit to the right, so we'll get:

#(0+1,-1+2)=(1,1)#

We can then plot the two points and connect them.

Graphed, it looks like this:

graph{2x-1 [-10, 10, -5, 5]}