Question

How do you solve `5x^2-3x+3=-2x^2+3`?

Answer 1

`x=0 and x=+3/7`

Explanation:

Given:`" "5x^2-3x+3=-2x^2+3`

Spot that we have:`" "5x^2-3x+cancel(3)=-2x^2+cancel(3)`

Add `2x^2` to both sides

`5x^2+2x^2-3x=-2x^2+2x^2`

`7x^2-3x=0`

Factor out the `x`

`x(7x-3)=0`

`x=0` is 1 solution

The other solution is that `7x-3=0`

`=>7x=+3`

`=>x=+3/7`
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`color(blue)("Plotting "y=5x^2-3x+3 and )`
`color(blue)(y=-2x^2+3" gives the same result")`