Question

Evaluate the indefinite integral: `int sin 35t sec^2 (cos 35t)dt`?

Answer 1

`-1/35tan(cos35t)+C`

Explanation:

`intsin35tsec^2(cos35t)dt`

Use the substitution `u=cos35t=>du=-35sin35t`.

`=-1/35intsec^2(cos35t)(-35sin35t)dt`

`=-1/35intsec^2(u)du`

This is a common integral:

`=-1/35tan(u)+C`

`=-1/35tan(cos35t)+C`