How do you simplify #2/sqrt7#?

1 Answer
MrsRudolph221
Jan 24, 2017

Multiply numerator and denominator by #sqrt(7)#:

Explanation:

#2/(sqrt(7))*(sqrt(7)/sqrt(7))# = #(2sqrt(7))/7#.
That is considered "rationalized" since the denominator is now a rational number, 7.

Example: Simplify #2/(3sqrt(12))#

Simplify the denominator first, then rationalize.
#2/(3sqrt(4)sqrt(3))#=#2/(3*2sqrt(3))#= #2/(6sqrt(3))#

and reduce the #2/6# = #1/(3sqrt(3))#.

NOW, multiply top and bottom by #sqrt(3)#:

#1/(3sqrt(3))*(sqrt(3)/(sqrt(3)))# = #(sqrt(3))/(3*3)#= #sqrt(3)/9#.

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
10520 views around the world
You can reuse this answer
Creative Commons License