What is -3x^4y^2 * -x^0y^-4 * 2x?

1 Answer
Jan 25, 2017

6x^5y^-2

Explanation:

Using the property of exponents, that a^b * a^c = a^(b+c):

-3x^2y^2 * -x^0y^-4 * 2x = -(-3) * 2 * x^(4 + 1 - 0) * y^(2-4)

= 6x^5y^-2 or (6x^5)/y^2. Note that the minus sign in front of x^0 does matter, even if it's attached to x^0, which is equal to 1 anyway.