If #f(x) = x+8# and #g(x) = x^2-6x-7#, what is #f(g(2))#?

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Answer 1 · 2017-01-26T17:37:37

The answer is #=-7#

This is a composition of functions

#f(x)=x+8#

#g(x)=x^2-6x-7#

#f(g(x))=f(x^2-6x-7)=x^2-6x-7+8#

#=x^2-6x+1#

Therefore,

#f(g(2))=2^2-6*2+1=4-12+1=-7#